4x^2+19x=5

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Solution for 4x^2+19x=5 equation:


Simplifying
4x2 + 19x = 5

Reorder the terms:
19x + 4x2 = 5

Solving
19x + 4x2 = 5

Solving for variable 'x'.

Reorder the terms:
-5 + 19x + 4x2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 19x + 4x2 = 0

Factor a trinomial.
(-5 + -1x)(1 + -4x) = 0

Subproblem 1

Set the factor '(-5 + -1x)' equal to zero and attempt to solve: Simplifying -5 + -1x = 0 Solving -5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1x = 0 + 5 -1x = 0 + 5 Combine like terms: 0 + 5 = 5 -1x = 5 Divide each side by '-1'. x = -5 Simplifying x = -5

Subproblem 2

Set the factor '(1 + -4x)' equal to zero and attempt to solve: Simplifying 1 + -4x = 0 Solving 1 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4x = 0 + -1 -4x = 0 + -1 Combine like terms: 0 + -1 = -1 -4x = -1 Divide each side by '-4'. x = 0.25 Simplifying x = 0.25

Solution

x = {-5, 0.25}

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